Optimal. Leaf size=135 \[ \frac{f (a+b x)^{m+1} (c+d x)^{1-m}}{2 b d}-\frac{(a+b x)^{m+1} (c+d x)^{-m} \left (\frac{b (c+d x)}{b c-a d}\right )^m (a d f (1-m)-b (2 d e-c f (m+1))) \, _2F_1\left (m,m+1;m+2;-\frac{d (a+b x)}{b c-a d}\right )}{2 b^2 d (m+1)} \]
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Rubi [A] time = 0.0599319, antiderivative size = 134, normalized size of antiderivative = 0.99, number of steps used = 3, number of rules used = 3, integrand size = 22, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.136, Rules used = {80, 70, 69} \[ \frac{(a+b x)^{m+1} (c+d x)^{-m} \left (\frac{b (c+d x)}{b c-a d}\right )^m (-a d f (1-m)-b c f (m+1)+2 b d e) \, _2F_1\left (m,m+1;m+2;-\frac{d (a+b x)}{b c-a d}\right )}{2 b^2 d (m+1)}+\frac{f (a+b x)^{m+1} (c+d x)^{1-m}}{2 b d} \]
Antiderivative was successfully verified.
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Rule 80
Rule 70
Rule 69
Rubi steps
\begin{align*} \int (a+b x)^m (c+d x)^{-m} (e+f x) \, dx &=\frac{f (a+b x)^{1+m} (c+d x)^{1-m}}{2 b d}+\frac{(2 b d e-f (a d (1-m)+b c (1+m))) \int (a+b x)^m (c+d x)^{-m} \, dx}{2 b d}\\ &=\frac{f (a+b x)^{1+m} (c+d x)^{1-m}}{2 b d}+\frac{\left ((2 b d e-f (a d (1-m)+b c (1+m))) (c+d x)^{-m} \left (\frac{b (c+d x)}{b c-a d}\right )^m\right ) \int (a+b x)^m \left (\frac{b c}{b c-a d}+\frac{b d x}{b c-a d}\right )^{-m} \, dx}{2 b d}\\ &=\frac{f (a+b x)^{1+m} (c+d x)^{1-m}}{2 b d}+\frac{(2 b d e-a d f (1-m)-b c f (1+m)) (a+b x)^{1+m} (c+d x)^{-m} \left (\frac{b (c+d x)}{b c-a d}\right )^m \, _2F_1\left (m,1+m;2+m;-\frac{d (a+b x)}{b c-a d}\right )}{2 b^2 d (1+m)}\\ \end{align*}
Mathematica [A] time = 0.0891403, size = 109, normalized size = 0.81 \[ \frac{(a+b x)^{m+1} (c+d x)^{-m} \left (b f (c+d x)-\frac{\left (\frac{b (c+d x)}{b c-a d}\right )^m (-a d f (m-1)+b c f (m+1)-2 b d e) \, _2F_1\left (m,m+1;m+2;\frac{d (a+b x)}{a d-b c}\right )}{m+1}\right )}{2 b^2 d} \]
Antiderivative was successfully verified.
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Maple [F] time = 0.055, size = 0, normalized size = 0. \begin{align*} \int{\frac{ \left ( fx+e \right ) \left ( bx+a \right ) ^{m}}{ \left ( dx+c \right ) ^{m}}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\left (f x + e\right )}{\left (b x + a\right )}^{m}}{{\left (d x + c\right )}^{m}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\frac{{\left (f x + e\right )}{\left (b x + a\right )}^{m}}{{\left (d x + c\right )}^{m}}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\left (f x + e\right )}{\left (b x + a\right )}^{m}}{{\left (d x + c\right )}^{m}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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